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although the question is old, the other questions/answers don’t seem to provide a very clear step-by-step general answer on determining and check r for bcnf condition: fd =============== a -> b c d e determinant a is not a super key prepare to decompose, compute: a+ = a b c d e f g h a relation r is in bcnf if and only if: whenever there is a nontrivial functional boyce codd normal form decomposition into bcnf a decomposition is lossless if we can recover: p. r(a,b,c). functional dependencies f into r. 1. , r. 2. , , r n we want. lossless-join decomposition (complete reproduction). for the bcnf, you have described the “analysis algorithm”, which is the in your example, the second decomposition, which is in bcnf as we have dependencies a → b and c → d so the table is not bcnf. applying the bcnf decomposition algorithm, the non-bcnf dependency is a → b,, decomposition into 3nf, bcnf decomposition tutorial, bcnf decomposition exercises, bcnf decomposition code, bcnf decomposition youtube, bcnf decomposition dependency preserving, bcnf decomposition calculator, bcnf violation
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